Cuk Converter: Derivation of Negative‑Output‑Voltage Formula

Ćuk Topology Schematic

(Images sourced from Microchip)

Derivation Steps

Step 1: Write inductor‑voltage equations for both switch states

State Voltage across L1 Voltage across L2
Q1 ON (D·T) VL1 = VIN VL2 = −VOUT − VC1
Q1 OFF ((1−D)·T) VL1 = VIN − VC1 VL2 = −VOUT

(Images sourced from Microchip)

Q1 ON

(Images sourced from Microchip)

Q1 OFF

For circuit analysis of Q1 ON / OFF, refer to:

Cuk Converter: Energy Flow Breakdown & Component Functions during Switch ON/OFF

Step 2: Apply Volt-Second Balance to L_1

Under steady-state conditions, the net volt-second product over one switching cycle equals zero:

V_{IN}\cdot D + (V_{IN}-V_{C1})\cdot(1-D)=0

Expand and simplify:

V_{IN}\cdot D + V_{IN}(1-D) - V_{C1}(1-D)=0

V_{IN}=V_{C1}(1-D)

Therefore:

\boxed{V_{C1}=\frac{V_{IN}}{1-D}}


Step 3: Apply Volt-Second Balance to L_2

(-V_{OUT}-V_{C1})\cdot D + (-V_{OUT})\cdot(1-D)=0

Expand and simplify:

-V_{OUT}\cdot D - V_{C1}\cdot D - V_{OUT}(1-D)=0

-V_{OUT}-V_{C1}\cdot D=0

Therefore:

\boxed{V_{OUT}=-V_{C1}\cdot D}


Step 4: Eliminate V_{C1} to Obtain the DC Transfer Function

Substitute

V_{C1}=\frac{V_{IN}}{1-D}

into the equation for V_{OUT}:

V_{OUT}=-\frac{V_{IN}}{1-D}\cdot D

Thus, the DC voltage conversion ratio of the Ćuk converter is:

\boxed{\frac{V_{OUT}}{V_{IN}}=-\frac{D}{1-D}}


Interpretation

Output Polarity

The negative sign indicates that the output voltage polarity is inverted relative to the input. Although the input and output share the same ground reference, the Ćuk converter produces a negative output voltage.

Output Voltage Magnitude

|V_{OUT}|=\frac{D}{1-D}\times V_{IN}

Depending on the duty cycle D:

  • D < 0.5 → Step-down operation

    |V_{OUT}| < V_{IN}

  • D = 0.5 → Equal magnitude

    |V_{OUT}| = V_{IN}

  • D > 0.5 → Step-up operation

    |V_{OUT}| > V_{IN}


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Additional References

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Cuk Applications

Cuk Operating Principles