Ok so i have 4 quantum boards im going to wire in series. And im confused how to wire up the dimmer potentiometer for the diming capability.
I have a HLG-480H-C2100B driver and the boards are 170 watts each. And i have a potentiometer dimmer from rapid led.
@Preybird1, based on the datasheet, the dimmer would get plugged in as so:
Do you have a part number on the Dimmer?
Regards,
Hi Preybird1,
Thanks for the inquiry. Your boards would be wired to Vo + and Vo - and the potentiometer would be wired to DIM- and DIM + as shown below. Hope this helps!
Here is the example from the data sheet showing how to connect your potentiometer.
Here’s another example showing how to connect the Meanwell driver to your potentiometer.
Hi Preybird,
You didn’t mention what the voltage and current ratings are for your “Quantum Boards”.
Assuming you are going to wire them in series, make sure that the voltage rating for four of them in series falls between the 114Vdc and 229Vdc rating of the HLG-480H-C2100B. That means each of them should be rated for between 29V and 57V.
Furthermore, make sure that the current rating of each of them is at least 2100mA. If it is less, you either need to select a different driver, or you need to be VERY careful not to over drive them. One can prevent over driving them by using the graph Robert showed above to set the maximum resistance seen between DIM+ and DIM-, and thereby set the maximum current, as a percentage of 2100mA. You can either do this by selecting a potentiometer with a resistance somewhat lower than 100K Ohms, or by placing a resistor in parallel with a 100K pot which makes an equivalent resistance no higher than the value you need according to that graph. For instance, putting a 1M Ohm resistor in parallel with a 100K pot would make a maximum parallel equivalent resistance of about 91K Ohms.
